Optics Question 1031

Question: Ratio of amplitude of interfering waves is 3 : 4. Now ratio of their intensities will be

[RPET 2000]

Options:

A) $ \frac{16}{9} $

B) 49 : 1

C) $ \frac{9}{16} $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ I\propto a^{2} $

$ \Rightarrow \frac{I _{1}}{I _{2}}={{( \frac{a _{1}}{a _{2}} )}^{2}} $

$ ={{( \frac{3}{4} )}^{2}}=\frac{9}{16} $



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