Optics Question 1031
Question: Ratio of amplitude of interfering waves is 3 : 4. Now ratio of their intensities will be
[RPET 2000]
Options:
A) $ \frac{16}{9} $
B) 49 : 1
C) $ \frac{9}{16} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ I\propto a^{2} $
$ \Rightarrow \frac{I _{1}}{I _{2}}={{( \frac{a _{1}}{a _{2}} )}^{2}} $
$ ={{( \frac{3}{4} )}^{2}}=\frac{9}{16} $
