Optics Question 1011

Question: If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima is

[MP PMT 1996]

Options:

A) 25 : 16

B) 5 : 3

C) 16 : 1

D) 25 : 9

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{a _{1}}{a _{2}}=\frac{3}{5} $

$ \therefore \frac{{I _{\max }}}{{I _{\min }}}=\frac{{{(a _{1}+a _{2})}^{2}}}{{{(a _{1}-a _{2})}^{2}}}=\frac{{{(3+5)}^{2}}}{{{(3-5)}^{2}}}=\frac{16}{1} $



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