Optics Question 1011
Question: If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima is
[MP PMT 1996]
Options:
A) 25 : 16
B) 5 : 3
C) 16 : 1
D) 25 : 9
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{a _{1}}{a _{2}}=\frac{3}{5} $
$ \therefore \frac{{I _{\max }}}{{I _{\min }}}=\frac{{{(a _{1}+a _{2})}^{2}}}{{{(a _{1}-a _{2})}^{2}}}=\frac{{{(3+5)}^{2}}}{{{(3-5)}^{2}}}=\frac{16}{1} $
