Laws Of Motion Question 428

Question: A sphere of mass m is held between two smooth inclined walls. For sin $ 37{}^\circ =3/5, $ the normal reaction of the wall (2) is equal to :

Options:

A) mg

B) $ mg\sin 74^{o} $

C) $ mg\cos 74^{o} $

D) none of the above

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Using Lami’s theorem $ \frac{mg}{\sin ({{180}^{\circ }}-{{37}^{\circ }})}=\frac{N _{2}}{\sin ({{180}^{\circ }}-{{37}^{\circ }})} $ $ \therefore $ $ N _{2}=mg $



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