Laws Of Motion Question 428
Question: A sphere of mass m is held between two smooth inclined walls. For sin $ 37{}^\circ =3/5, $ the normal reaction of the wall (2) is equal to :
Options:
A) mg
B) $ mg\sin 74^{o} $
C) $ mg\cos 74^{o} $
D) none of the above
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Using Lami’s theorem $ \frac{mg}{\sin ({{180}^{\circ }}-{{37}^{\circ }})}=\frac{N _{2}}{\sin ({{180}^{\circ }}-{{37}^{\circ }})} $ $ \therefore $ $ N _{2}=mg $
