Laws Of Motion Question 353

Question: Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown. The coefficient of static friction of A with table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is[MP PET 1984]

Options:

A) 15 kg

B) 10 kg

C) 5 kg

D) 12 kg

Show Answer

Answer:

Correct Answer: A

Solution:

For limiting condition $ \mu =\frac{m _{B}}{m _{A}+m _{C}} $

therefore $ 0.2=\frac{5}{10+m _{C}} $

therefore $ 2+0.2m _{C}=5 $

therefore $ m _{C}=15kg $



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