Laws Of Motion Question 353
Question: Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown. The coefficient of static friction of A with table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is[MP PET 1984]
Options:
A) 15 kg
B) 10 kg
C) 5 kg
D) 12 kg
Show Answer
Answer:
Correct Answer: A
Solution:
For limiting condition $ \mu =\frac{m _{B}}{m _{A}+m _{C}} $
therefore $ 0.2=\frac{5}{10+m _{C}} $
therefore $ 2+0.2m _{C}=5 $
therefore $ m _{C}=15kg $
