Laws Of Motion Question 315

Question: Two blocks $ m _{1}=5gm $ and$ m _{2}=gm $ are hung vertically over a light frictionless pulley as shown here. What is the acceleration of the masses when they are left free? (Where g is acceleration due to gravity)

Options:

A) $ g/3 $

B) $ g/2 $

C) $ g $

D) $ g/5 $

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Answer:

Correct Answer: A

Solution:

[a] Let T be the tension in the string.

$ \therefore 10g-T=10a …(i)$

$ T-5g=5a ..(ii) $

Adding (i) and (ii), $5g=15a\Rightarrow a=\frac{g}{3}m/s^{2}$



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