Laws Of Motion Question 315
Question: Two blocks $ m _{1}=5gm $ and$ m _{2}=gm $ are hung vertically over a light frictionless pulley as shown here. What is the acceleration of the masses when they are left free? (Where g is acceleration due to gravity)
Options:
A) $ g/3 $
B) $ g/2 $
C) $ g $
D) $ g/5 $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Let T be the tension in the string.
$ \therefore 10g-T=10a …(i)$
$ T-5g=5a ..(ii) $
Adding (i) and (ii), $5g=15a\Rightarrow a=\frac{g}{3}m/s^{2}$
