SATHEE: Laws Of Motion Question 288

Laws Of Motion Question 288

Question: Two bodies of masses 1 kg and 2 kg moving with same velocities are stopped by the same force. Then the ratio of their stopping distances is

Options:

A) $1 : 2$

B) $2 : 1$

C) (c) $\sqrt{2} : 1$

D) $1 : \sqrt{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $S = \frac{V^{2} - U^{2}}{2 a} and a = F / m, so$

$\frac{S_{1}}{S_{2}} = \frac{(\frac{0 - U^{2}}{2 F / m})}{(\frac{0 - U^{2}}{2 F / 2 m})} = 1.2$

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