Laws Of Motion Question 274

Question: One end of string of length l is connected to a particle of mass ’m’ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed V the net force on the particle (directed towards center) will be (T represents the tension in the string)

Options:

A) $ T+\frac{mv^{2}}{l} $

B)$ T-\frac{mv^{2}}{l} $

C)Zero

D) T

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Net force on particle in uniform circular motion is centripetal force

$ ( \frac{mv^{2}}{l} ) $

which is provided by tension in string so the net force will be equal to tension i.e., T.



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