Laws Of Motion Question 274
Question: One end of string of length l is connected to a particle of mass ’m’ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed V the net force on the particle (directed towards center) will be (T represents the tension in the string)
Options:
A) $ T+\frac{mv^{2}}{l} $
B)$ T-\frac{mv^{2}}{l} $
C)Zero
D) T
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Net force on particle in uniform circular motion is centripetal force
$ ( \frac{mv^{2}}{l} ) $
which is provided by tension in string so the net force will be equal to tension i.e., T.
