Laws Of Motion Question 230

Question: If rope of lift breaks suddenly, the tension exerted by the surface of lift [AFMC 2002] (a = acceleration of lift)

Options:

A) mg

B) $ m(g+a) $

C) $ m(g-a) $

D) $ 0 $

Show Answer

Answer:

Correct Answer: D

Solution:

If rope of lift breaks suddenly, acceleration becomes equal to g so that tension, $ T=m(g-g)=0 $



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