Laws Of Motion Question 230
Question: If rope of lift breaks suddenly, the tension exerted by the surface of lift [AFMC 2002] (a = acceleration of lift)
Options:
A) mg
B) $ m(g+a) $
C) $ m(g-a) $
D) $ 0 $
Show Answer
Answer:
Correct Answer: D
Solution:
If rope of lift breaks suddenly, acceleration becomes equal to g so that tension, $ T=m(g-g)=0 $
