Laws Of Motion Question 221
Question: The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.2s is [RPET 2000]
Options:
A) 12.5 N
B) 25 N
C) 50 N
D) 100 N
Show Answer
Answer:
Correct Answer: A
Solution:
$ F=m( \frac{v-u}{t} )=\frac{5(65-15)\times {{10}^{-2}}}{0.2}=12.5N $
