Laws Of Motion Question 221

Question: The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.2s is [RPET 2000]

Options:

A) 12.5 N

B) 25 N

C) 50 N

D) 100 N

Show Answer

Answer:

Correct Answer: A

Solution:

$ F=m( \frac{v-u}{t} )=\frac{5(65-15)\times {{10}^{-2}}}{0.2}=12.5N $



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