Laws Of Motion Question 157
Question: Three blocks of masses $ m _{1},m _{2} $ and $ m _{3} $ are connected by massless strings as shown on a frictionless table. They are pulled with a force $ T _{3}=40N $ . If $ m _{1}=10kg,m _{2}=6kg $ and $ m _{3}=4kg $ , the tension $ T _{2} $ will be [MP PMT/PET 1998]
Options:
A) 20 N
B) 40 N
C) 10 N
D) 32 N
Show Answer
Answer:
Correct Answer: D
Solution:
$ T _{2}=(m _{1}+m _{2})\times \frac{T _{3}}{m _{1}+m _{2}+m _{3}}=\frac{(10+6)\times 40}{20} $
$ =32\ N $
