Laws Of Motion Question 111
Question: A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of $ 1m{{s}^{-2}} $ . If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is [SCRA 1998]
Options:
A) 3000 N
B) 4000 N
C) 5000 N
D) 6000 N
Show Answer
Answer:
Correct Answer: D
Solution:
Net force in forward direction = Accelerating force + Friction $ =ma+\mu \ mg=m(a+\mu \ g)=(1500+500)(1+0.2\times 10) $
$ =2000\times 3=6000\ N $
