Laws Of Motion Question 111

Question: A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of $ 1m{{s}^{-2}} $ . If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is [SCRA 1998]

Options:

A) 3000 N

B) 4000 N

C) 5000 N

D) 6000 N

Show Answer

Answer:

Correct Answer: D

Solution:

Net force in forward direction = Accelerating force + Friction $ =ma+\mu \ mg=m(a+\mu \ g)=(1500+500)(1+0.2\times 10) $

$ =2000\times 3=6000\ N $



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