Laws Of Motion Question 106

Question: On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and$ g=10m/s^{2} $ , the body will stop after covering a distance of [MP PMT 1999]

Options:

A) 10 m

B) 25 m

C) 50 m

D) 250 m

Show Answer

Answer:

Correct Answer: B

Solution:

$ S=\frac{u^{2}}{2\mu g}=\frac{{{(10)}^{2}}}{2\times 0.2\times 10}=25\ m $



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