Laws Of Motion Question 106
Question: On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and$ g=10m/s^{2} $ , the body will stop after covering a distance of [MP PMT 1999]
Options:
A) 10 m
B) 25 m
C) 50 m
D) 250 m
Show Answer
Answer:
Correct Answer: B
Solution:
$ S=\frac{u^{2}}{2\mu g}=\frac{{{(10)}^{2}}}{2\times 0.2\times 10}=25\ m $
