SATHEE: Kinematics Question 792

Kinematics Question 792

Question: The acceleration of a train travelling with speed of 400 m/s as it goes round a curve of radius 160 m, it’s [Pb. PET 2003]

Options:

A) $1 k m / s^{2}$

B) $100 m / s^{2}$

C) $10 m / s^{2}$

D) $1 m / s^{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

$a = \frac{v^{2}}{r} = \frac{{(400)}^{2}}{160} = 10^{3} m / s^{2} = 1 k m / s^{2}$

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