Kinematics Question 792
Question: The acceleration of a train travelling with speed of 400 m/s as it goes round a curve of radius 160 m, it’s [Pb. PET 2003]
Options:
A) $ 1km/s^{2} $
B)$ 100m/s^{2} $
C) $ 10m/s^{2} $
D) $ 1m/s^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ a=\frac{v^{2}}{r}=\frac{{{(400)}^{2}}}{160}=10^{3}m/s^{2}=1km/s^{2} $
