Kinematics Question 778

Question: A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is [Or it’ssa JEE 2002]

Options:

A) $ 2\pi v/T $

B)$ 2\pi r/T $

C) $ 2\pi r^{2}/T $

D) $ 2\pi v^{2}/T $

Show Answer

Answer:

Correct Answer: A

Solution:

Acceleration$ ={{\omega }^{2}}r=\frac{v^{2}}{r}=\omega v=\frac{2\pi }{T}v $



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