Kinematics Question 778
Question: A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is [Or it’ssa JEE 2002]
Options:
A) $ 2\pi v/T $
B)$ 2\pi r/T $
C) $ 2\pi r^{2}/T $
D) $ 2\pi v^{2}/T $
Show Answer
Answer:
Correct Answer: A
Solution:
Acceleration$ ={{\omega }^{2}}r=\frac{v^{2}}{r}=\omega v=\frac{2\pi }{T}v $
