Kinematics Question 763
Question: A 100 kg car is moving with a maximum velocity of 9 m/s across a circular track of radius 30 m.The maximum force of friction between the road and the car it’s[Pb. PMT 2000]
Options:
A) 1000 N
B)706 N
C) 270 N
D) 200 N
Show Answer
Answer:
Correct Answer: C
Solution:
Maximum force of friction = centripetal force $ \frac{mv^{2}}{r}=\frac{100\times {{(9)}^{2}}}{30}=270N $
