Kinematics Question 763

Question: A 100 kg car is moving with a maximum velocity of 9 m/s across a circular track of radius 30 m.The maximum force of friction between the road and the car it’s[Pb. PMT 2000]

Options:

A) 1000 N

B)706 N

C) 270 N

D) 200 N

Show Answer

Answer:

Correct Answer: C

Solution:

Maximum force of friction = centripetal force $ \frac{mv^{2}}{r}=\frac{100\times {{(9)}^{2}}}{30}=270N $



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