Kinematics Question 750

Question: The angular speed of seconds needle in a mechanical watch is [RPMT 1999; CPMT 1997; MH CET 2000, 01; BHU 2000]

Options:

A) $ \frac{\pi }{30} $ rad/s

B)$ 2\pi $ rad/s

C) $ \pi $ rad/s

D)$ \frac{60}{\pi } $ rad/s

Show Answer

Answer:

Correct Answer: A

Solution:

$ \omega =\frac{2\pi }{T}=\frac{2\pi }{60}=\frac{\pi }{30}rad/s $



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