Kinematics Question 750
Question: The angular speed of seconds needle in a mechanical watch is [RPMT 1999; CPMT 1997; MH CET 2000, 01; BHU 2000]
Options:
A) $ \frac{\pi }{30} $ rad/s
B)$ 2\pi $ rad/s
C) $ \pi $ rad/s
D)$ \frac{60}{\pi } $ rad/s
Show Answer
Answer:
Correct Answer: A
Solution:
$ \omega =\frac{2\pi }{T}=\frac{2\pi }{60}=\frac{\pi }{30}rad/s $
