Kinematics Question 688
Question: Referring to above question, the angle with the horizontal at which the projectile was projected it’s
Options:
A) $ {{\tan }^{-1}}(3/4 $ )
B) $ {{\tan }^{-1}}(4/3) $
C) $ {{\sin }^{-1}}(3/4 $ )
D) Not obtainable from the given data
Show Answer
Answer:
Correct Answer: B
Solution:
[b] The angle of projection is given by $ \theta ={{\tan }^{-1}}( \frac{v _{y}}{v _{x}} )={{\tan }^{-1}}( \frac{4}{3} ) $
