Kinematics Question 688

Question: Referring to above question, the angle with the horizontal at which the projectile was projected it’s

Options:

A) $ {{\tan }^{-1}}(3/4 $ )

B) $ {{\tan }^{-1}}(4/3) $

C) $ {{\sin }^{-1}}(3/4 $ )

D) Not obtainable from the given data

Show Answer

Answer:

Correct Answer: B

Solution:

[b] The angle of projection is given by $ \theta ={{\tan }^{-1}}( \frac{v _{y}}{v _{x}} )={{\tan }^{-1}}( \frac{4}{3} ) $



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