Kinematics Question 686
Question: An object is thrown along a direction inclined at an angle of $ 45^{o} $ with the horizontal direction. The horizontal range of the particle is equal to
Options:
A) Vertical height
B) Twice the vertical height
C) Thrice the vertical height
D) Four times the vertical height
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ R=4H\cot \theta $ if $ \theta =45{}^\circ $ then $ R=4H\cot (45{}^\circ )=4H $
