Kinematics Question 686

Question: An object is thrown along a direction inclined at an angle of $ 45^{o} $ with the horizontal direction. The horizontal range of the particle is equal to

Options:

A) Vertical height

B) Twice the vertical height

C) Thrice the vertical height

D) Four times the vertical height

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ R=4H\cot \theta $ if $ \theta =45{}^\circ $ then $ R=4H\cot (45{}^\circ )=4H $



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