Kinematics Question 654
Question: The length of second’s hand in a watch is 1 cm. The change in velocity of it’s tip in 15 seconds is:
Options:
A) zero
B) $ \frac{\pi }{30\sqrt{2}}\text{ cm/s} $
C) $ \frac{\pi }{30}\text{ cm/s} $
D)$ \frac{\pi \sqrt{2}}{30}\text{ cm/s} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \Delta \text{v}=\sqrt{2}v=\sqrt{2}\omega \text{r}=\sqrt{2}( \frac{2\pi }{60} )\times 1=\frac{\pi \sqrt{2}}{30}cm\text{/}s $
