Kinematics Question 654

Question: The length of second’s hand in a watch is 1 cm. The change in velocity of it’s tip in 15 seconds is:

Options:

A) zero

B) $ \frac{\pi }{30\sqrt{2}}\text{ cm/s} $

C) $ \frac{\pi }{30}\text{ cm/s} $

D)$ \frac{\pi \sqrt{2}}{30}\text{ cm/s} $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ \Delta \text{v}=\sqrt{2}v=\sqrt{2}\omega \text{r}=\sqrt{2}( \frac{2\pi }{60} )\times 1=\frac{\pi \sqrt{2}}{30}cm\text{/}s $



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