Kinematics Question 629
Question: A particle is projected at angle $ 37{}^\circ $ with the incline plane in upward direction with speed 10 m/s. The angle of incline plane is given $ 53{}^\circ $ . Then the maximum height attained by the particle from the incline plane will be
Options:
A) 3 m
B)4 m
C) 5 m
D)zero
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ H=\frac{{u _{\bot }}^{2}}{2{g _{\bot }}}\Rightarrow H=\frac{10\sin 37{}^\circ \times 10\sin 37{}^\circ }{2\times g\cos 53{}^\circ }=3m $
