Kinematics Question 629

Question: A particle is projected at angle $ 37{}^\circ $ with the incline plane in upward direction with speed 10 m/s. The angle of incline plane is given $ 53{}^\circ $ . Then the maximum height attained by the particle from the incline plane will be

Options:

A) 3 m

B)4 m

C) 5 m

D)zero

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ H=\frac{{u _{\bot }}^{2}}{2{g _{\bot }}}\Rightarrow H=\frac{10\sin 37{}^\circ \times 10\sin 37{}^\circ }{2\times g\cos 53{}^\circ }=3m $



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