Kinematics Question 617
Question: A projectile is given an initial velocity of $ ( \hat{i}+2\hat{j} )m/s $ , where; it’s along the ground and j it’s along the vertical. If $ g=10m/s^{2} $ , the equation of it’s trajectory it’s :
Options:
A) $ y=x-5x^{2} $
B)$ y=2x-5x^{2} $
C) $ 4y=2x-5{{x}^{2~}}~ $
D)$ 4y=2x-25x^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] From equation, $ \vec{v}=\hat{i}+2\hat{j} $
$ \Rightarrow x=t $ …(i) $ y=2t-\frac{1}{2}( 10t^{2} ) $ …(ii) From (i) and (ii), $ y=2x-5x^{2} $
