Kinematics Question 617

Question: A projectile is given an initial velocity of $ ( \hat{i}+2\hat{j} )m/s $ , where; it’s along the ground and j it’s along the vertical. If $ g=10m/s^{2} $ , the equation of it’s trajectory it’s :

Options:

A) $ y=x-5x^{2} $

B)$ y=2x-5x^{2} $

C) $ 4y=2x-5{{x}^{2~}}~ $

D)$ 4y=2x-25x^{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] From equation, $ \vec{v}=\hat{i}+2\hat{j} $

$ \Rightarrow x=t $ …(i) $ y=2t-\frac{1}{2}( 10t^{2} ) $ …(ii) From (i) and (ii), $ y=2x-5x^{2} $



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