SATHEE: Kinematics Question 616

Kinematics Question 616

Question: A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be

Options:

A) 20 $\sqrt{2}$ m

B)10 m

C) 10 $\sqrt{2}$ m

D) 20 m

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $R = \frac{u^{2} \sin^{2} θ}{g}, H = \frac{u^{2} \sin^{2} θ}{2 g}$

$H_{max} at 2 θ = 90^{\circ} So, H_{max} = \frac{u^{2}}{2g}$

$\frac{u^{2}}{2g} = 10 \Rightarrow u^{2} = 10 g \times 2$

$R = \frac{u^{2} \sin 2 θ}{g} \Rightarrow R_{max} = \frac{u^{2}}{2g} = 20 meter .$

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