Kinematics Question 616
Question: A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be
Options:
A) 20$ \sqrt{2} $ m
B)10 m
C) 10$ \sqrt{2} $ m
D) 20 m
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \text{R}\text{=}\frac{{{u^{2}}}{{\sin }^{2}}\theta }{g},\text{ H}\text{=}\frac{{{u^{2}}}{{\sin }^{2}}\theta }{2g} $
$ {{\text{H}} _{\max }}\text{ at 2}\theta \text{=}\text{90}{}^\circ \text{ So, }{{\text{H}} _{\max }}=\frac{{{u^{2}}}}{\text{2g}} $
$ \frac{{{u^{2}}}}{\text{2g}}=10\Rightarrow {{u^{2}}}=10g\times 2 $
$ R=\frac{{{u^{2}}}\sin 2\theta }{g}\Rightarrow {R _{\max }}=\frac{{{u^{2}}}}{\text{2g}}=20\text{ meter}\text{.} $
