SATHEE: Kinematics Question 609

Kinematics Question 609

Question: The equation of a projectile is $y = \sqrt{3} x - \frac{g}{x^{2}} 20$ The angle of projection is given by

Options:

A) $tan θ = \frac{1}{\sqrt{3}}$

B) $tan θ = \sqrt{3}$

C) $\frac{π}{2}$

D) zero.

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Comparing the given equation with

$y = x \tan θ - \frac{g}{x^{2}} 2 u^{2} \cos^{2} θ, we get$

$tan θ = \sqrt{3}$

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Kinematics Question 609

Question: The equation of a projectile is y=3x−gx220 The angle of projection is given by

Options:

Answer:

Solution:

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Question: The equation of a projectile is $y = \sqrt{3} x - \frac{g}{x^{2}} 20$ The angle of projection is given by