Kinematics Question 609
Question: The equation of a projectile is $ y=\sqrt{3}x-\frac{\text{g}}{{x^{2}}}{20} $ The angle of projection is given by
Options:
A) $ \text{tan}\theta \text{=}\frac{1}{\sqrt{3}} $
B)$ \text{tan}\theta \text{=}\sqrt{3} $
C)$ \frac{\pi }{2} $
D) zero.
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Comparing the given equation with
$ y=x\tan \theta -\frac{\text{g}}{{x^{2}}}{2{{u^{2}}}{{\cos }^{2}}\theta },\text{ we get} $
$ \text{tan}\theta \text{=}\sqrt{3} $
