Kinematics Question 548
Question: The tension in the string revolving in a vertical circle with a mass$ m $ at the end Which is at the lowest position [EAMCET (Engg.) 1995; AIIMS 2001]
Options:
A) $ \frac{mv^{2}}{r} $
B)$ \frac{mv^{2}}{r}-mg $
C) $ \frac{mv^{2}}{r}+mg $
D)$ mg $
Show Answer
Answer:
Correct Answer: C
Solution:
Tension = Centrifugal force + weight $ =\frac{mv^{2}}{r}+mg $
