Kinematics Question 548

Question: The tension in the string revolving in a vertical circle with a mass$ m $ at the end Which is at the lowest position [EAMCET (Engg.) 1995; AIIMS 2001]

Options:

A) $ \frac{mv^{2}}{r} $

B)$ \frac{mv^{2}}{r}-mg $

C) $ \frac{mv^{2}}{r}+mg $

D)$ mg $

Show Answer

Answer:

Correct Answer: C

Solution:

Tension = Centrifugal force + weight $ =\frac{mv^{2}}{r}+mg $



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