SATHEE: Kinematics Question 448

Kinematics Question 448

Question: $\vec{A} - \vec{B}$ and $\vec{A}$ are parallel. If $| \vec{A} \times \vec{B} | = | \vec{A} . \vec{B} |,$ then angle between $\vec{A}$ and $\vec{B}$ will be

Options:

A) $30^{\circ}$

B) $45^{\circ}$

C) $60^{\circ}$

D) $90^{\circ}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $| \vec{A} \times \vec{B} | = \vec{A} . \vec{B}$

$\Rightarrow$ $A B \sin θ = A B \cos θ$

$\Rightarrow$ $\tan θ = 1$

$∴$ $θ = 45^{o}$

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Kinematics Question 448

Question: A→−B→ and A→ are parallel. If |A→×B→|=|A→.B→|, then angle between A→ and B→ will be

Options:

Answer:

Solution:

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Question: $\vec{A} - \vec{B}$ and $\vec{A}$ are parallel. If $| \vec{A} \times \vec{B} | = | \vec{A} . \vec{B} |,$ then angle between $\vec{A}$ and $\vec{B}$ will be