Kinematics Question 448
Question: $ \vec{A}-\vec{B} $ and $ \vec{A} $ are parallel. If $ |\vec{A}\times \vec{B}|=|\vec{A}.\vec{B}|, $ then angle between $ \vec{A} $ and $ \vec{B} $ will be
Options:
A) $ 30{}^\circ $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 90{}^\circ $
Correct Answer: B [b] $ | \overrightarrow{A}\times \overrightarrow{B} |=\overrightarrow{A}.\overrightarrow{B} $ $ \Rightarrow $ $ AB\sin \theta =AB\cos \theta $ $ \Rightarrow $ $ \tan \theta =1 $ $ \therefore $ $ \theta =45^{o} $
Show Answer
Answer:
Solution:
