Kinematics Question 435
Question: P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given $ P=1.9318kgwt, $ $ sin{\theta_1}=0.9659, $ the value of R it’s (in kg wt)
Options:
A) 0.9659
B) 2
C) 1
D) $ \frac{1}{2} $
Correct Answer: C [c] $ \frac{P}{\sin {\theta_1}}=\frac{Q}{\sin {\theta_2}}=\frac{R}{\sin 150^{o}} $ $ \Rightarrow $ $ \frac{1.93}{\sin {\theta_1}}=\frac{R}{\sin 150^{o}} $ $ \Rightarrow $ $ R=\frac{1.93\times \sin 150^{o}}{\sin {\theta_1}}=\frac{1.93\times 0.5}{0.9659}=1 $
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