Kinematics Question 435

Question: P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given $ P=1.9318kgwt, $ $ sin{\theta_1}=0.9659, $ the value of R it’s (in kg wt)

Options:

A) 0.9659

B) 2

C) 1

D) $ \frac{1}{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ \frac{P}{\sin {\theta_1}}=\frac{Q}{\sin {\theta_2}}=\frac{R}{\sin 150^{o}} $

$ \Rightarrow $ $ \frac{1.93}{\sin {\theta_1}}=\frac{R}{\sin 150^{o}} $

$ \Rightarrow $ $ R=\frac{1.93\times \sin 150^{o}}{\sin {\theta_1}}=\frac{1.93\times 0.5}{0.9659}=1 $



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